CPS610 Assignment 3 solved

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Assignment3- For this assignment you only need one instance of Oracle (use installed
Oracle 11g+ on your laptop or school oracle.scs.ryerson.ca).
Use the following examples and create and populate two new Professors Table with the
following attributes:
1- Create Professor1 Table to have an address included as an object. See example
below which adds address as an object (user defined type) to a table called
addresses.
2- Create Professor2 Table to contain a circular object type in a way that is similar to
MARRIEDPERSON TABLE shown below.
3- Based on your observations explain what is REF
4- Add an attribute to show the number courses a professor is teaching in the
professor object and then use PL/SQL and write a procedure to increase the
number of courses a professor is teaching. You can look at the following link to
learn fundamentual of PL/SQL: https://w3resource.com/plsql-exercises/
Submit the source code of you assignment during lab 8- March 19
————–USE Following Template—————————————————————
SQL> CREATE TYPE address_typ AS OBJECT
2 (StreetNo NUMBER(10),
3 StreetName VARCHAR2(100),
4 AptNo NUMBER(5),
5 City VARCHAR2(100),
6 State VARCHAR2(100),
7 ZipCode NUMBER(9),
8 Country VARCHAR2(100));
9 /
CREATE TYPE address_typ AS OBJECT
SQL> CREATE TABLE addresses of address_typ;
Table created.
SQL> SELECT REF(e) FROM addresses e;
no rows selected
SQL> insert into addresses
values(114, ‘third’, 2, ‘San Mateo’,’California’,43000, ‘USA’);
1 row created.
SQL> SELECT REF(e) FROM addresses e;
REF(E)
——————————————————————————–
0000280209B27053838222FAF6E040758D0DE70423B27053838221FAF6E040758D0
DE70423018000
AF0000
SQL> CREATE TYPE person_t AS OBJECT
(name VARCHAR2(20),
address address_typ);
Type created.
SQL> CREATE TABLE PERSON of person_t;
Table created.
SQL> INSERT INTO PERSON
VALUES(‘John’, address_typ(112, ‘Park Place’, 2, ‘San Mateo’,’California’,43000,
‘USA’));
1 row created.
SQL> SELECT VALUE(e) from PERSON e;
VALUE(E)(NAME, ADDRESS(STREETNO, STREETNAME, APTNO, CITY,
STATE, ZIPCODE, COUNTR
——————————————————————————–
PERSON_T(‘John’, ADDRESS_TYP(112, ‘Park Place’, 2, ‘San Mateo’, ‘California’, 43
000, ‘USA’))
SQL> SELECT REF(e) FROM PERSON e;
REF(E)
——————————————————————————–
0000280209B27053838229FAF6E040758D0DE70423B27053838228FAF6E040758D0
DE70423018000
BF0000
Creating Circular Object Type
SQL> create type married_person_t as object
(Name VARCHAR2(10),
Spouse REF married_person_t);

Type created.
SQL> create table MARRIEDPERSON of married_person_t;
Table created.
SQL> insert into MARRIEDPERSON(Name)
values(‘John’);
1 row created.
SQL> select * from MARRIEDPERSON
2 ;
NAME
———-
SPOUSE
——————————————————————————–
John
SQL> insert into MARRIEDPERSON
2 select ‘Sara’, REF(M)
3 from MARRIEDPERSON M
4 where Name=’John’;
1 row created.
SQL> select * from MARRIEDPERSON;
NAME
———-
SPOUSE
——————————————————————————–
John
Sara
0000220208B27E849E8B2C7493E040758D0DE7186AB27E849E8B277493E040758D0
DE7186A
SQL> update MARRIEDPERSON
2 Set Spouse =
3 (select REF(M)
4 from MARRIEDPERSON M
5 where M.Name=’Sara’)
6 where Name=’John’;
1 row updated.
SQL> select * from MARRIEDPERSON;
NAME
———-
SPOUSE
——————————————————————————–
John
0000220208B27E849E8B2D7493E040758D0DE7186AB27E849E8B277493E040758D
0DE7186A
Sara
0000220208B27E849E8B2C7493E040758D0DE7186AB27E849E8B277493E040758D0
DE7186A