# CMPT 280– Intermediate Data Structures and Algoirthms Assignment 2 solved

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2 Background
2.1 Timing Analysis
Questions 1 through 10 in Section 3 concern timing analysis. These questions are not programming
questions and should be submitted in one of the acceptable document formats listed above.
2.2 Arrayed Trees
Question 11 is about a bounded binary tree implementation. You should remember binary trees from CMPT
115 (or similar course) – they are trees in which each node has at most two children. What you probably
didn’t know is that binary trees can be stored using an array, rather than a linked structure. In such an array,
the contents of the root node are stored in offset 1 of the array (offset 0 is unused). The contents of the
children of the node whose contents are stored at offset i are stored at offset 2i and 2i + 1, respectively.
Thus, the left child of the root is at offset 2 1 = 2, the right child of the root is at offset 2 1 + 1 = 3, the left
child of the left child of the root is at offset 2 2 = 4, and so on. The parent of the node whose contents are
at offset i, is at offset i/2 (integer division). Thus, the parent of node at offset 7 is at offset 3.
Example 1
Here is the array representation of a tree storing the elements 1 through 10, in no particular order. The array
– 7 1 4 3 9 10 2 8 5 6
is a representation of the tree:
Note that we do not allow any unused cells in the array between used ones. All the nodes in the array
are stored contiguously. This means that we can represent only a particular subset of binary trees with this
representation. Namely, it is the set of trees where all levels except possibly the last level are complete (full)
and the nodes in the last level are all as far to the left as possible. You might be thinking that this is too
restrictive and not very useful because we can’t represent all binary trees with this data structure. However,
as we will see on future assignments, this array-based tree data structure is highly useful and efficient for
implementing certain other important data structures.
Also note that if we read off the items from left to right in each level of the tree, starting from the top
level, we get the items in the same order as they appear in the array (we will visit this again when studying

Page 2
Question 1 ():
Suppose the exact time required for an algorithm A is given by:
𝑇𝐴

(a) (2 points) Which of the following statements are true?
1. Algorithm A is O(log n)
2. Algoirthm A is O(n)
3. Algoirthm A is O(n3
)
4. Algoirthm A is O(2n
)
(b) (1 point) Give the correct time complexity for A in big-Θ notation.
Question 2 ():
For each of the following functions, give the tightest upper bound chosen from among the usual simple
functions listed in Section 4.5 of the course readings. Answers should be expressed in big-O notation.
7
1 4
3 9 10 2
8 5 6
Question 3 ():
If possible, simplify the following expressions. Hint: See slide 11 of topic 4 of the lecture slides!
(a) (1 point) O(n2
) + O (log n) + O (n log n)
(b) (1 point) O(2n
) O(n2
)
(c) (1 point) 42O (n log n) + 18O(n3
)
(d) (1 point) O (n2
log2 n
2
) + O (m) (yes, that’s an ‘m’, not a typo; note that m is independent of n)
Question 4 (5 points): Consider the function f (n) = 2n3 + 5n2 + 42. Use the definition of big-O
to prove that f (n) ϵ O(n3
).
Question 5 (5 points):
Consider the function g(n) = 12n2
log n2 + 6n + 42. Use the definition of big-O to prove that g(n) ϵ
O(n2
log n2
).
Question 6 (3 points):
Consider again the function g(n) = 12n2
log n2 + 6n + 42. Use the definition of big-O to prove that g(n)
is not in O(n).
Question 7 ():
Consider the following Java code fragment:
// Print out all ordered pairs of numbers between 1 and
n for (i = 1; i <= n; i++) { for (j = 1; j <= n; j++) { System .out. println ( i + ", " + j) ; } } (a) (3 points) Determine the exact number of statements (i.e. the statement counting approach) that are executed when we run this code fragment as a function of n. Show all of your calculations. (b) (1 point) Express the function you obtained in part a) in big-Θ notation. Page 3 Question 8 (): Consider the following pseudocode: Algorithm roundRobinTournament (a) This algorithm generates the list of matches that must be played in a round - robin pirate - dueling tournament (a tournament where each pirate duels each other pirate exactly once). a is an array of strings containing names of entrants into a tournament n = a.length for i = 0 to n-1 for j = i+1 to n-1 print a[i] + " duels " + a[j] + ", Yarrr!" (a) (5 points) Determine the exact number of statements (i.e. use the statement counting approach that are executed by the above algorithm. Express your answer as a function of n. Show all your calculations. (b) (1 point) Express the function you obtained in part a) in big-Θ notation. Question 9 (): Consider the following pseudocode: Algorithm moveDown (a) a is an array of numbers int i = 1 n = a.length while (a[i] > a[2*i] || a[i] > a[2*i+1]) && 2*i+1 < n) if a[2*i] >= a[2*i +1]
largest = 2*i
else
largest = 2*i + 1
temp = a[i]
a[i] = a[largest]
a[largest] = temp
i = largest
(a) (2 points) Determine the exact number of statements (i.e. use the statement counting approach)
that are executed during one iteration of the while loop in the worst case. Your answer should be
expressed in terms of n (the length of the array) Show all calculations.
(b) (5 points) Determine the exact number of times the while loop executes in the worst case.
(c) (3 points) Determine the exact number of statements executed in the worst case by the whole
algorithm.
(d) (1 point) Identify an Active Operation
(e) (2 points) Determine the exact number of times the active operation is executed.
(f) (2 points) Express the answers to parts c) and e) in big-O notation.

Question 1 0 (28 points):
Your task is to write a Java class called ArrayedBinaryTreeWithCursors280 which extends and
implements the abstract class ArrayedBinaryTree280 (provided in the lib280-asn2.tree package
as
part of lib280-asn2). This week’s lab will also talk more about array-based trees.
Some of the work of implementing ArrayedBinaryTreeWithCursors280 has already been done.
There are several methods in defined in ArrayedBinaryTreeWithCursors280 which are defined but not
implemented; these are marked with //TODO comments. Note that ArrayedBinaryTreeWithCursors280
also implements the interfaces Dict280 and Cursor280. There are several missing methods required by these interfaces that also needed to be implemented. The headers for these are not yet
present in ArrayedBinaryTreeWithCursors280 – you need to add them. Until you do, the com-piler
will complain on line 15 that there are unimplemented abstract methods inherited from the interfaces.
The interfaces Dict280 and Cursor280 and their ancestors (yes, they have ancestor interfaces!)
document what these methods are supposed to do.
You may not modify any of the existing code in the provided ArrayedBinaryTreeWithCursors280.java
file, but you can add to it. You may also not modify any other files within lib280-asn2.
implementation of the arrayed binary tree should pass the given regression test. If all the regression
tests are successful, the only output should be: Regression test complete.
Hint: one of your first major decisions after adding the appropriate method headers for the inherited abstract
methods will be to start implementing the insert method and decide where the new element
should be inserted. If you think about it, there’s really only one place it can go…
Hint: The algorithm for deleting an element is to replace the element to be deleted by the right-most element
in the bottom level of the tree, then delete the right-most element in the bottom level of the tree.
Reminder: the elements of the items array (defined in the abstract class ArrayedBinaryTree280 )
represent the nodes of the tree. You are storing the contents of nodes in the array. There is no node class.
It is very important that the contents of the root are stored in offset 1 and we don’t use cell 0 of the array,
otherwise, the given formulae for finding the child or parent of a node at offset i will not work correctly.
4 Files Provided
lib280-asn2: A copy of lib280 which includes solutions to assignment 1, the ArrayedBinaryTree280
abstract class, and the partially completed ArrayedBinaryTreeWithCursors280 class for Question
11. The ArrayedTree280 interface can be found in the lib280-asn2.tree package.
5 What to Hand In
You must submit the following files:
Q1-10.doc/docx/rtf/pdf/txt – your answers to questions 1 through 10. Digital images of handwritten
pages are also acceptable, provided that they are clearly legible.
ArrayedBinaryTreeWithCursors280.java – your arrayed binary tree implementation and regression test.